What are the solutions to the equation 3y^2+15y=0 ?

The solutions to the equation 3y^2+15y=0 are y=0,y=-5

Find the zeros of 3y^2+15y=0

The zeros of 3y^2+15y=0 are y=0,y=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} + 15 y = 0

y = 0, y = - 5

Solution steps

3 y^{2} + 15 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 \cdot 0 = 15

y_{1, 2} = \frac{- 15 \pm 15}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 15 + 15}{2 \cdot 3}, y_{2} = \frac{- 15 - 15}{2 \cdot 3}

y = \frac{- 15 + 15}{2 \cdot 3} : 0

y = \frac{- 15 - 15}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

y = 0, y = - 5

4 q + 5 \geq 6 q - 7

2 x^{2} + 6 x^{3} + 5 x^{7} + 15 x^{8}

(2 x - 3) \cdot (3 x + 8) = 0

lo g_{0.5} (2)

- \frac{3}{4} - \frac{7}{8}

What are the solutions to the equation 3y^2+15y=0 ?
The solutions to the equation 3y^2+15y=0 are y=0,y=-5
Find the zeros of 3y^2+15y=0
The zeros of 3y^2+15y=0 are y=0,y=-5