What are the solutions to the equation 4=x^2 ?

The solutions to the equation 4=x^2 are x=2,x=-2

Find the zeros of 4=x^2

The zeros of 4=x^2 are x=2,x=-2

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4 = x^{2}

x = 2, x = - 2

Solution steps

4 = x^{2}

Switch sides

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

2 x^{2} - 2 x + 2 = 0

4 x - 7 + x = 10 - 3 x - 1

\frac{5}{12} + \frac{11}{18}

\frac{- 1}{x - 6} < \frac{2}{9 - x}

(2 + 2)^{2}

What are the solutions to the equation 4=x^2 ?
The solutions to the equation 4=x^2 are x=2,x=-2
Find the zeros of 4=x^2
The zeros of 4=x^2 are x=2,x=-2