What is the answer to x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5 ?

The answer to x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5 is x=0

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x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5

x^{4} - 4 x^{3} + 3 x^{2} + 4 x - 4 = (1 - x)^{4} - 3 x^{2} + 2 x - 5

x = 0

Solution steps

x^{4} - 4 x^{3} + 3 x^{2} + 4 x - 4 = (1 - x)^{4} - 3 x^{2} + 2 x - 5

Expand

(1 - x)^{4} - 3 x^{2} + 2 x - 5 : x^{4} - 4 x^{3} + 3 x^{2} - 2 x - 4

x^{4} - 4 x^{3} + 3 x^{2} + 4 x - 4 = x^{4} - 4 x^{3} + 3 x^{2} - 2 x - 4

Move

4

to the right side

x^{4} - 4 x^{3} + 3 x^{2} + 4 x = x^{4} - 4 x^{3} + 3 x^{2} - 2 x

Subtract

x^{4} - 4 x^{3} + 3 x^{2} - 2 x

from both sides

x^{4} - 4 x^{3} + 3 x^{2} + 4 x - (x^{4} - 4 x^{3} + 3 x^{2} - 2 x) = x^{4} - 4 x^{3} + 3 x^{2} - 2 x - (x^{4} - 4 x^{3} + 3 x^{2} - 2 x)

Simplify

6 x = 0

Divide both sides by

6

x = 0

6 x^{3} - 7 x^{2} - 11 x + 12

12 + 4

42 + 12 u = 2

81 x^{2} - 121 = 0

x^{2} = - 8 + 6 x

What is the answer to x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5 ?
The answer to x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5 is x=0
Solve for x: x^4-4x^3+3x^2+4x-4=(1-x)^4-3x^2+2x-5
The solution is x=0