What are the solutions to the equation ((x-1)(x+1))/(20+1)=5 ?

The solutions to the equation ((x-1)(x+1))/(20+1)=5 are x=sqrt(106),x=-sqrt(106)

Find the zeros of ((x-1)(x+1))/(20+1)=5

The zeros of ((x-1)(x+1))/(20+1)=5 are x=sqrt(106),x=-sqrt(106)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{( x - 1 ) ( x + 1 )}{20 + 1} = 5

x = 106, x = - 106

Decimal Notation

x = 10.29563 \dots, x = - 10.29563 \dots

Solution steps

\frac{( x - 1 ) ( x + 1 )}{20 + 1} = 5

Simplify

20 + 1 : 21

\frac{( x - 1 ) ( x + 1 )}{21} = 5

Multiply both sides by

21

(x - 1) (x + 1) = 105

Expand

(x - 1) (x + 1) : x^{2} - 1

x^{2} - 1 = 105

Move

105

to the left side

x^{2} - 106 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 106 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 106) = 2106

x_{1, 2} = \frac{- 0 \pm 2 106}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 106}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 106}{2 \cdot 1}

x = \frac{- 0 + 2 106}{2 \cdot 1} : 106

x = \frac{- 0 - 2 106}{2 \cdot 1} : - 106

The solutions to the quadratic equation are:

x = 106, x = - 106

\frac{1}{2} \cdot 6 \cdot 10

(\frac{3 x y ^{2}}{4 w z}) (\frac{6 x ^{3}}{5 w ^{2} y})

- 84 = s (s + 19)

\frac{a}{3 b}

x^{2} - 8 x + 3 = 0

What are the solutions to the equation ((x-1)(x+1))/(20+1)=5 ?
The solutions to the equation ((x-1)(x+1))/(20+1)=5 are x=sqrt(106),x=-sqrt(106)
Find the zeros of ((x-1)(x+1))/(20+1)=5
The zeros of ((x-1)(x+1))/(20+1)=5 are x=sqrt(106),x=-sqrt(106)