What is (10!)/(2!(10-2)!) ?

The solution to (10!)/(2!(10-2)!) is 45

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simplify (10!)/(2!(10-2)!)

simplify

\frac{10 !}{2 ! ( 10 - 2 ) !}

45

Solution steps

\frac{10 !}{2 ! ( 10 - 2 ) !}

Subtract the numbers:

10 - 2 = 8

= \frac{10 !}{2 ! \cdot 8 !}

Cancel the factorials:

\frac{n !}{( n - m ) !} = n \cdot (n - 1) \dots (n - m + 1), n > m

\frac{10 !}{8 !} = 10 \cdot 9

= \frac{10 \cdot 9}{2 !}

\frac{10 \cdot 9}{2 !} = 45

= 45

\frac{3}{2} + \frac{2}{3} + 1

3 \times 2

\frac{( 1 + i ) ( 1 - 2 i )}{( 2 + i ) ( 4 - 3 i )}

13 = \frac{1}{2} (3 x + 8)

- 3 x^{2} + 6 x + 5 = 0