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Popular >

x^2+2x+1<= 0

Solution

x^{2} + 2 x + 1 \leq 0

Solution

x = - 1

+1

Interval Notation

x = - 1

Solution steps

x^{2} + 2 x + 1 \leq 0

Factor

x^{2} + 2 x + 1 : (x + 1)^{2}

(x + 1)^{2} \leq 0

For

u^{n} \leq 0

, if

n

is even then

u = 0

x + 1 = 0

Move

1

to the right side

x = - 1

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(a - b)^{3}

2y^2+y-9=(y-1)^2

2 y^{2} + y - 9 = (y - 1)^{2}

4 x^{2} - 8 x = - 19

Frequently Asked Questions (FAQ)

What is x^2+2x+1<= 0 ?
The solution to x^2+2x+1<= 0 is x=-1