What are the solutions to the equation -6x^2+6-2x=x ?

The solutions to the equation -6x^2+6-2x=x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

Find the zeros of -6x^2+6-2x=x

The zeros of -6x^2+6-2x=x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

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- 6 x^{2} + 6 - 2 x = x

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

Decimal Notation

x = - 1.28077 \dots, x = 0.78077 \dots

Solution steps

- 6 x^{2} + 6 - 2 x = x

Move

x

to the left side

- 6 x^{2} + 6 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 3)^{2} - 4 (- 6) \cdot 6 = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )}

x = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )} : - \frac{1 + 17}{4}

x = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )} : \frac{17 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

a^{2} - 4 a - 5

\frac{- 18 m ^{2} n}{6 mn}

3 + 4 i

4 b^{4} - 9 b^{2}

16 (4 x - 1)^{2} - 46 = 35

What are the solutions to the equation -6x^2+6-2x=x ?
The solutions to the equation -6x^2+6-2x=x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4
Find the zeros of -6x^2+6-2x=x
The zeros of -6x^2+6-2x=x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4