What are the solutions to the equation 16(4x-1)^2-46=35 ?

The solutions to the equation 16(4x-1)^2-46=35 are x= 13/16 ,x=-5/16

Find the zeros of 16(4x-1)^2-46=35

The zeros of 16(4x-1)^2-46=35 are x= 13/16 ,x=-5/16

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16 (4 x - 1)^{2} - 46 = 35

x = \frac{13}{16}, x = - \frac{5}{16}

Solution steps

16 (4 x - 1)^{2} - 46 = 35

Move

46

to the right side

16 (4 x - 1)^{2} = 81

Divide both sides by

16

(4 x - 1)^{2} = \frac{81}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = \frac{81}{16} : x = \frac{13}{16}

Solve

4 x - 1 = - \frac{81}{16} : x = - \frac{5}{16}

The solutions to the quadratic equation are:

x = \frac{13}{16}, x = - \frac{5}{16}

3 m^{2} - 7 m + 4

y^{2} + 4 y + 5 y = 0

(x - 9)^{2} = 16

\frac{1}{2} x - 3 > 2

t^{2} + 7 t - 2 = 0

What are the solutions to the equation 16(4x-1)^2-46=35 ?
The solutions to the equation 16(4x-1)^2-46=35 are x= 13/16 ,x=-5/16
Find the zeros of 16(4x-1)^2-46=35
The zeros of 16(4x-1)^2-46=35 are x= 13/16 ,x=-5/16