What are the solutions to the equation y^2+4y+5y=0 ?

The solutions to the equation y^2+4y+5y=0 are y=0,y=-9

Find the zeros of y^2+4y+5y=0

The zeros of y^2+4y+5y=0 are y=0,y=-9

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y^{2} + 4 y + 5 y = 0

y = 0, y = - 9

Solution steps

y^{2} + 4 y + 5 y = 0

Refine

y^{2} + 9 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 0 = 9

y_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 9 + 9}{2 \cdot 1}, y_{2} = \frac{- 9 - 9}{2 \cdot 1}

y = \frac{- 9 + 9}{2 \cdot 1} : 0

y = \frac{- 9 - 9}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

y = 0, y = - 9

(x - 9)^{2} = 16

\frac{1}{2} x - 3 > 2

t^{2} + 7 t - 2 = 0

3025

x^{2} + 8 x + 12

What are the solutions to the equation y^2+4y+5y=0 ?
The solutions to the equation y^2+4y+5y=0 are y=0,y=-9
Find the zeros of y^2+4y+5y=0
The zeros of y^2+4y+5y=0 are y=0,y=-9