What are the solutions to the equation 1/2 (x-3)^2-8=0 ?

The solutions to the equation 1/2 (x-3)^2-8=0 are x=7,x=-1

Find the zeros of 1/2 (x-3)^2-8=0

The zeros of 1/2 (x-3)^2-8=0 are x=7,x=-1

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\frac{1}{2} (x - 3)^{2} - 8 = 0

x = 7, x = - 1

Solution steps

\frac{1}{2} (x - 3)^{2} - 8 = 0

Move

8

to the right side

\frac{1}{2} (x - 3)^{2} = 8

Multiply both sides by

2

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

3 x + 4 < 22

(x + 4)^{2} + 4 = 85

9 a^{2} - 64 b^{2}

10

(x + 7)^{2} - 49 = 0

What are the solutions to the equation 1/2 (x-3)^2-8=0 ?
The solutions to the equation 1/2 (x-3)^2-8=0 are x=7,x=-1
Find the zeros of 1/2 (x-3)^2-8=0
The zeros of 1/2 (x-3)^2-8=0 are x=7,x=-1