What are the solutions to the equation w^2-7w=30 ?

The solutions to the equation w^2-7w=30 are w=10,w=-3

Find the zeros of w^2-7w=30

The zeros of w^2-7w=30 are w=10,w=-3

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w^{2} - 7 w = 30

w = 10, w = - 3

Solution steps

w^{2} - 7 w = 30

Move

30

to the left side

w^{2} - 7 w - 30 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 30) = 13

w_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 1}, w_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 1}

w = \frac{- ( - 7 ) + 13}{2 \cdot 1} : 10

w = \frac{- ( - 7 ) - 13}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

w = 10, w = - 3

- 3 x = 10

- 10

x^{2} + x - \frac{5}{3} = 0

9 h^{3} - 6 h

\frac{x}{2} - \frac{x}{3} = \frac{1}{6} (x - \frac{3}{2}) + x

What are the solutions to the equation w^2-7w=30 ?
The solutions to the equation w^2-7w=30 are w=10,w=-3
Find the zeros of w^2-7w=30
The zeros of w^2-7w=30 are w=10,w=-3