What are the solutions to the equation 3x^2=-x ?

The solutions to the equation 3x^2=-x are x=0,x=-1/3

Find the zeros of 3x^2=-x

The zeros of 3x^2=-x are x=0,x=-1/3

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3 x^{2} = - x

x = 0, x = - \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots

Solution steps

3 x^{2} = - x

Move

x

to the left side

3 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1^{2} - 4 \cdot 3 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 3}, x_{2} = \frac{- 1 - 1}{2 \cdot 3}

x = \frac{- 1 + 1}{2 \cdot 3} : 0

x = \frac{- 1 - 1}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{3}

\frac{2}{7} - 1

x^{2} + 3 x - 18 > 0

(\frac{1}{2} - \frac{1}{4} i) (\frac{2}{3} + \frac{5}{3} i)

(8 x + 1)^{2} - (8 x + 1) - 12 = 0

\frac{3 - x}{x - 4} \leq 2

What are the solutions to the equation 3x^2=-x ?
The solutions to the equation 3x^2=-x are x=0,x=-1/3
Find the zeros of 3x^2=-x
The zeros of 3x^2=-x are x=0,x=-1/3