What are the solutions to the equation x^2-7x+6=0 ?

The solutions to the equation x^2-7x+6=0 are x=6,x=1

Find the zeros of x^2-7x+6=0

The zeros of x^2-7x+6=0 are x=6,x=1

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x^{2} - 7 x + 6 = 0

x = 6, x = 1

Solution steps

x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

x = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

x = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 6, x = 1

lo g_{49} (343)

\frac{1}{2} x + 3 < 4 x - 7

(5 a - 3 b)^{2} - 25 a^{2}

- 2 (3 y - 6) + 4 (5 y - 8) = 92

What are the solutions to the equation x^2-7x+6=0 ?
The solutions to the equation x^2-7x+6=0 are x=6,x=1
Find the zeros of x^2-7x+6=0
The zeros of x^2-7x+6=0 are x=6,x=1