What are the solutions to the equation 4s^2+4s+1=0 ?

The solutions to the equation 4s^2+4s+1=0 are s=-1/2

Find the zeros of 4s^2+4s+1=0

The zeros of 4s^2+4s+1=0 are s=-1/2

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4 s^{2} + 4 s + 1 = 0

s = - \frac{1}{2}

Decimal Notation

s = - 0.5

Solution steps

4 s^{2} + 4 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

s_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

s = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

s = - \frac{1}{2}

The solution to the quadratic equation is:

s = - \frac{1}{2}

y^{2} + 7 y - 11 = 0

3 x + 2 > 5

810

- 3 k \leq - 6

(5^{4})^{\frac{1}{2}}

What are the solutions to the equation 4s^2+4s+1=0 ?
The solutions to the equation 4s^2+4s+1=0 are s=-1/2
Find the zeros of 4s^2+4s+1=0
The zeros of 4s^2+4s+1=0 are s=-1/2