What are the solutions to the equation 3x^2+4x-6=0 ?

The solutions to the equation 3x^2+4x-6=0 are x=(-2+sqrt(22))/3 ,x=-(2+sqrt(22))/3

Find the zeros of 3x^2+4x-6=0

The zeros of 3x^2+4x-6=0 are x=(-2+sqrt(22))/3 ,x=-(2+sqrt(22))/3

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3 x^{2} + 4 x - 6 = 0

x = \frac{- 2 + 22}{3}, x = - \frac{2 + 22}{3}

Solution steps

3 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 6) = 222

x_{1, 2} = \frac{- 4 \pm 2 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 22}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 22}{2 \cdot 3}

x = \frac{- 4 + 2 22}{2 \cdot 3} : \frac{- 2 + 22}{3}

x = \frac{- 4 - 2 22}{2 \cdot 3} : - \frac{2 + 22}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 22}{3}, x = - \frac{2 + 22}{3}

2 x^{2} - 7 x = 5

\frac{5}{3} + 6

2 x^{2} - 9 x - 56

3 x^{2} - 4 x + 7 = 0

- 4 + x + 7 x^{2} = 0

What are the solutions to the equation 3x^2+4x-6=0 ?
The solutions to the equation 3x^2+4x-6=0 are x=(-2+sqrt(22))/3 ,x=-(2+sqrt(22))/3
Find the zeros of 3x^2+4x-6=0
The zeros of 3x^2+4x-6=0 are x=(-2+sqrt(22))/3 ,x=-(2+sqrt(22))/3