What are the solutions to the equation 3x^2-4x+7=0 ?

The solutions to the equation 3x^2-4x+7=0 are x= 2/3+i(sqrt(17))/3 ,x= 2/3-i(sqrt(17))/3

Find the zeros of 3x^2-4x+7=0

The zeros of 3x^2-4x+7=0 are x= 2/3+i(sqrt(17))/3 ,x= 2/3-i(sqrt(17))/3

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3 x^{2} - 4 x + 7 = 0

x = \frac{2}{3} + i \frac{17}{3}, x = \frac{2}{3} - i \frac{17}{3}

Solution steps

3 x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 7 : 217 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 17 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 17 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 17 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 17 i}{2 \cdot 3} : \frac{2}{3} + i \frac{17}{3}

x = \frac{- ( - 4 ) - 2 17 i}{2 \cdot 3} : \frac{2}{3} - i \frac{17}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{17}{3}, x = \frac{2}{3} - i \frac{17}{3}

- 4 + x + 7 x^{2} = 0

\frac{1}{100} + \frac{1}{200} + \frac{1}{300}

3 x + 12 - 6 x \leq - 9

(\frac{1}{8})^{3}

12 a^{2} + 16 ab - 3 b^{2}

What are the solutions to the equation 3x^2-4x+7=0 ?
The solutions to the equation 3x^2-4x+7=0 are x= 2/3+i(sqrt(17))/3 ,x= 2/3-i(sqrt(17))/3
Find the zeros of 3x^2-4x+7=0
The zeros of 3x^2-4x+7=0 are x= 2/3+i(sqrt(17))/3 ,x= 2/3-i(sqrt(17))/3