What are the solutions to the equation 2t^2-12t=12 ?

The solutions to the equation 2t^2-12t=12 are t=3+sqrt(15),t=3-sqrt(15)

Find the zeros of 2t^2-12t=12

The zeros of 2t^2-12t=12 are t=3+sqrt(15),t=3-sqrt(15)

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2 t^{2} - 12 t = 12

t = 3 + 15, t = 3 - 15

Decimal Notation

t = 6.87298 \dots, t = - 0.87298 \dots

Solution steps

2 t^{2} - 12 t = 12

Move

12

to the left side

2 t^{2} - 12 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 12) = 415

t_{1, 2} = \frac{- ( - 12 ) \pm 4 15}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 4 15}{2 \cdot 2}, t_{2} = \frac{- ( - 12 ) - 4 15}{2 \cdot 2}

t = \frac{- ( - 12 ) + 4 15}{2 \cdot 2} : 3 + 15

t = \frac{- ( - 12 ) - 4 15}{2 \cdot 2} : 3 - 15

The solutions to the quadratic equation are:

t = 3 + 15, t = 3 - 15

500 u^{3} + 4 x^{3}

x (3 x - 18) (6 x - 48) \geq 0

x^{2} + 2 x + 18 = 0

\frac{3 z ^{2} - 13 z + 4}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

9 x^{7} y^{5} - 3 x^{2} y^{6}

What are the solutions to the equation 2t^2-12t=12 ?
The solutions to the equation 2t^2-12t=12 are t=3+sqrt(15),t=3-sqrt(15)
Find the zeros of 2t^2-12t=12
The zeros of 2t^2-12t=12 are t=3+sqrt(15),t=3-sqrt(15)