What are the solutions to the equation x^2+2x+18=0 ?

The solutions to the equation x^2+2x+18=0 are x=-1+sqrt(17)i,x=-1-sqrt(17)i

Find the zeros of x^2+2x+18=0

The zeros of x^2+2x+18=0 are x=-1+sqrt(17)i,x=-1-sqrt(17)i

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x^{2} + 2 x + 18 = 0

x = - 1 + 17 i, x = - 1 - 17 i

Solution steps

x^{2} + 2 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 18 : 217 i

x_{1, 2} = \frac{- 2 \pm 2 17 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 17 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 17 i}{2 \cdot 1}

x = \frac{- 2 + 2 17 i}{2 \cdot 1} : - 1 + 17 i

x = \frac{- 2 - 2 17 i}{2 \cdot 1} : - 1 - 17 i

The solutions to the quadratic equation are:

x = - 1 + 17 i, x = - 1 - 17 i

\frac{3 z ^{2} - 13 z + 4}{z ^{4} - 2 z ^{3} - 8 z ^{2}}

9 x^{7} y^{5} - 3 x^{2} y^{6}

3 x^{2} - 42 x + 147

z + 3 (z + 7) = - 5

4 x^{2} = 9 x

What are the solutions to the equation x^2+2x+18=0 ?
The solutions to the equation x^2+2x+18=0 are x=-1+sqrt(17)i,x=-1-sqrt(17)i
Find the zeros of x^2+2x+18=0
The zeros of x^2+2x+18=0 are x=-1+sqrt(17)i,x=-1-sqrt(17)i