What are the solutions to the equation 4x^2-15=25 ?

The solutions to the equation 4x^2-15=25 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 4x^2-15=25

The zeros of 4x^2-15=25 are x=sqrt(10),x=-sqrt(10)

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4 x^{2} - 15 = 25

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

4 x^{2} - 15 = 25

Move

15

to the right side

4 x^{2} = 40

Divide both sides by

4

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

- 6 (x + 3) = 3 (x - 15)

4 x^{2} + 5 x = 2

∣ x - 8 ∣ < 1

5 x - 2 \geq 68

(\frac{16}{625})^{\frac{1}{4}}

What are the solutions to the equation 4x^2-15=25 ?
The solutions to the equation 4x^2-15=25 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 4x^2-15=25
The zeros of 4x^2-15=25 are x=sqrt(10),x=-sqrt(10)