What is factor 3a^2+4a-4 ?

The solution to factor 3a^2+4a-4 is (3a-2)(a+2)

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factor 3a^2+4a-4

factor

3 a^{2} + 4 a - 4

(3 a - 2) (a + 2)

Solution steps

3 a^{2} + 4 a - 4

Break the expression into groups

= (3 a^{2} - 2 a) + (6 a - 4)

Factor out

a

from

3 a^{2} - 2 a : a (3 a - 2)

Factor out

2

from

6 a - 4 : 2 (3 a - 2)

= a (3 a - 2) + 2 (3 a - 2)

Factor out common term

3 a - 2

= (3 a - 2) (a + 2)

\frac{8 ^{4}}{4 ^{4}}

2 (3 - x)^{2} + \frac{1}{2} = \frac{5}{2}

3 x^{2} + 7 x + 2 = 0

4 x^{2} - 13 = 0

s^{2} + 4