What are the solutions to the equation 25x^2+16=0 ?

The solutions to the equation 25x^2+16=0 are x= 4/5 i,x=-4/5 i

Find the zeros of 25x^2+16=0

The zeros of 25x^2+16=0 are x= 4/5 i,x=-4/5 i

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25 x^{2} + 16 = 0

x = \frac{4}{5} i, x = - \frac{4}{5} i

Solution steps

25 x^{2} + 16 = 0

Move

16

to the right side

25 x^{2} = - 16

Divide both sides by

25

x^{2} = - \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{16}{25}, x = - - \frac{16}{25}

- \frac{16}{25} = \frac{4}{5} i

- - \frac{16}{25} = - \frac{4}{5} i

x = \frac{4}{5} i, x = - \frac{4}{5} i

3 x^{2} + 2 = 7 x

2 (\frac{x}{3} + 5) = \frac{2 x}{4} + 4

3 x = \frac{1}{2} - 9 + \frac{3}{2}

x - 4 = 2

- 4 x + 7 > - 25 or 7 x + 2 \geq - 19

What are the solutions to the equation 25x^2+16=0 ?
The solutions to the equation 25x^2+16=0 are x= 4/5 i,x=-4/5 i
Find the zeros of 25x^2+16=0
The zeros of 25x^2+16=0 are x= 4/5 i,x=-4/5 i