What are the solutions to the equation 4x^2+9x=-3 ?

The solutions to the equation 4x^2+9x=-3 are x=(-9+sqrt(33))/8 ,x=(-9-sqrt(33))/8

Find the zeros of 4x^2+9x=-3

The zeros of 4x^2+9x=-3 are x=(-9+sqrt(33))/8 ,x=(-9-sqrt(33))/8

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4 x^{2} + 9 x = - 3

x = \frac{- 9 + 33}{8}, x = \frac{- 9 - 33}{8}

Decimal Notation

x = - 0.40692 \dots, x = - 1.84307 \dots

Solution steps

4 x^{2} + 9 x = - 3

Move

3

to the left side

4 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 3 = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 4}, x_{2} = \frac{- 9 - 33}{2 \cdot 4}

x = \frac{- 9 + 33}{2 \cdot 4} : \frac{- 9 + 33}{8}

x = \frac{- 9 - 33}{2 \cdot 4} : \frac{- 9 - 33}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 33}{8}, x = \frac{- 9 - 33}{8}

\frac{k ( 4 - k )}{4} > 0

\frac{7 i}{4 + 4 i}

2 x - 2 (3 x - 5) < x

x^{2} + 11 x + 32 = 0

3 r^{2} - 8 r + 5

What are the solutions to the equation 4x^2+9x=-3 ?
The solutions to the equation 4x^2+9x=-3 are x=(-9+sqrt(33))/8 ,x=(-9-sqrt(33))/8
Find the zeros of 4x^2+9x=-3
The zeros of 4x^2+9x=-3 are x=(-9+sqrt(33))/8 ,x=(-9-sqrt(33))/8