What are the solutions to the equation 0=205-11t-16t^2 ?

The solutions to the equation 0=205-11t-16t^2 are t=-(11+sqrt(13241))/(32),t=(sqrt(13241)-11)/(32)

Find the zeros of 0=205-11t-16t^2

The zeros of 0=205-11t-16t^2 are t=-(11+sqrt(13241))/(32),t=(sqrt(13241)-11)/(32)

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0 = 205 - 11 t - 16 t^{2}

t = - \frac{11 + 13241}{32}, t = \frac{13241 - 11}{32}

Decimal Notation

t = - 3.93967 \dots, t = 3.25217 \dots

Solution steps

0 = 205 - 11 t - 16 t^{2}

Switch sides

205 - 11 t - 16 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 t^{2} - 11 t + 205 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 ( - 16 ) \cdot 205}{2 ( - 16 )}

(- 11)^{2} - 4 (- 16) \cdot 205 = 13241

t_{1, 2} = \frac{- ( - 11 ) \pm 13241}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- ( - 11 ) + 13241}{2 ( - 16 )}, t_{2} = \frac{- ( - 11 ) - 13241}{2 ( - 16 )}

t = \frac{- ( - 11 ) + 13241}{2 ( - 16 )} : - \frac{11 + 13241}{32}

t = \frac{- ( - 11 ) - 13241}{2 ( - 16 )} : \frac{13241 - 11}{32}

The solutions to the quadratic equation are:

t = - \frac{11 + 13241}{32}, t = \frac{13241 - 11}{32}

3 - 2 x - x^{2} = 0

7 x^{2} - 14 x - 21

\frac{- x}{4} - \frac{x}{3} = 14

15 \cdot 6 \cdot 12 \cdot 1 0^{- 2}

4 (x - 2) = x + 10

What are the solutions to the equation 0=205-11t-16t^2 ?
The solutions to the equation 0=205-11t-16t^2 are t=-(11+sqrt(13241))/(32),t=(sqrt(13241)-11)/(32)
Find the zeros of 0=205-11t-16t^2
The zeros of 0=205-11t-16t^2 are t=-(11+sqrt(13241))/(32),t=(sqrt(13241)-11)/(32)