What are the solutions to the equation 0=x^2-2x+3 ?

The solutions to the equation 0=x^2-2x+3 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 0=x^2-2x+3

The zeros of 0=x^2-2x+3 are x=1+sqrt(2)i,x=1-sqrt(2)i

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0 = x^{2} - 2 x + 3

x = 1 + 2 i, x = 1 - 2 i

Solution steps

0 = x^{2} - 2 x + 3

Switch sides

x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

\frac{x - 4 y}{5 x} - \frac{4 x}{3 x}

\frac{x}{2} \geq 10

6 x (x - 7) < 2 (3 x - 1) (x - 8)

x^{2} + 4 = 56

b^{- 6} \cdot b^{11}

What are the solutions to the equation 0=x^2-2x+3 ?
The solutions to the equation 0=x^2-2x+3 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 0=x^2-2x+3
The zeros of 0=x^2-2x+3 are x=1+sqrt(2)i,x=1-sqrt(2)i