What are the solutions to the equation n^2-9n+18=0 ?

The solutions to the equation n^2-9n+18=0 are n=6,n=3

Find the zeros of n^2-9n+18=0

The zeros of n^2-9n+18=0 are n=6,n=3

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n^{2} - 9 n + 18 = 0

n = 6, n = 3

Solution steps

n^{2} - 9 n + 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

n_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

n = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

n = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

n = 6, n = 3

4 t - 7 = 14 - 3 t

3 x + 17 = x + 3

x^{2} - 5 x + 4 > 0

x^{2} + \frac{3}{4} x + \frac{1}{8} = 0

x = 2 x + 3

What are the solutions to the equation n^2-9n+18=0 ?
The solutions to the equation n^2-9n+18=0 are n=6,n=3
Find the zeros of n^2-9n+18=0
The zeros of n^2-9n+18=0 are n=6,n=3