What is x^4-4x^3-x^2+4x<= 0 ?

The solution to x^4-4x^3-x^2+4x<= 0 is -1<= x<= 0\lor 1<= x<= 4

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x^4-4x^3-x^2+4x<= 0

x^{4} - 4 x^{3} - x^{2} + 4 x \leq 0

- 1 \leq x \leq 0 or 1 \leq x \leq 4

Interval Notation

[- 1, 0] \cup [1, 4]

Solution steps

x^{4} - 4 x^{3} - x^{2} + 4 x \leq 0

Factor

x^{4} - 4 x^{3} - x^{2} + 4 x : x (x - 4) (x + 1) (x - 1)

x (x - 4) (x + 1) (x - 1) \leq 0

Identify the intervals

- 1 \leq x \leq 0 or 1 \leq x \leq 4

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x^{2} - 70 x + 600 = 0

3 a^{3} b^{2} - 5 a^{3} b^{2}

7 y - 4 + 3 y + 6 = 9 y + 8

\frac{( 2 x ^{4} - 6 x ^{2} + 4 x )}{( 6 x ^{4} - 12 x ^{3} + 6 x ^{2} )}

What is x^4-4x^3-x^2+4x<= 0 ?
The solution to x^4-4x^3-x^2+4x<= 0 is -1<= x<= 0\lor 1<= x<= 4