What are the solutions to the equation -3x^2+6x+24=0 ?

The solutions to the equation -3x^2+6x+24=0 are x=-2,x=4

Find the zeros of -3x^2+6x+24=0

The zeros of -3x^2+6x+24=0 are x=-2,x=4

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- 3 x^{2} + 6 x + 24 = 0

x = - 2, x = 4

Solution steps

- 3 x^{2} + 6 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 24}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 24 = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 ( - 3 )}, x_{2} = \frac{- 6 - 18}{2 ( - 3 )}

x = \frac{- 6 + 18}{2 ( - 3 )} : - 2

x = \frac{- 6 - 18}{2 ( - 3 )} : 4

The solutions to the quadratic equation are:

x = - 2, x = 4

\frac{12}{5} y \geq - \frac{36}{5}

- 2 x^{2} + 20 x - 52 = 0

- \frac{2}{5} - 3

2 x^{2} - 7 x + 4 = 0

(2 m + 3)^{2} + 6 (2 m + 3) + 5 = 0

What are the solutions to the equation -3x^2+6x+24=0 ?
The solutions to the equation -3x^2+6x+24=0 are x=-2,x=4
Find the zeros of -3x^2+6x+24=0
The zeros of -3x^2+6x+24=0 are x=-2,x=4