What are the solutions to the equation -x^2+4=3x+4 ?

The solutions to the equation -x^2+4=3x+4 are x=-3,x=0

Find the zeros of -x^2+4=3x+4

The zeros of -x^2+4=3x+4 are x=-3,x=0

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- x^{2} + 4 = 3 x + 4

x = - 3, x = 0

Solution steps

- x^{2} + 4 = 3 x + 4

Move

4

to the left side

- x^{2} = 3 x

Move

3 x

to the left side

- x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 1 )} : - 3

x = \frac{- ( - 3 ) - 3}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

x = - 3, x = 0

4 x^{2} + 20 x y + 25 y^{2}

\frac{24}{1.60218 \cdot 1 0 ^{- 19}}

\frac{2}{3} + \frac{3 t}{4} = \frac{31}{6}

64 x^{3} + 27 y^{3}

\frac{2 0 ^{0.4} - 1}{\frac{1060}{300} - 1}

What are the solutions to the equation -x^2+4=3x+4 ?
The solutions to the equation -x^2+4=3x+4 are x=-3,x=0
Find the zeros of -x^2+4=3x+4
The zeros of -x^2+4=3x+4 are x=-3,x=0