What are the solutions to the equation 7p^2-38p-24=0 ?

The solutions to the equation 7p^2-38p-24=0 are p=6,p=-4/7

Find the zeros of 7p^2-38p-24=0

The zeros of 7p^2-38p-24=0 are p=6,p=-4/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 p^{2} - 38 p - 24 = 0

p = 6, p = - \frac{4}{7}

Decimal Notation

p = 6, p = - 0.57142 \dots

Solution steps

7 p^{2} - 38 p - 24 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 38 ) \pm ( - 38 ) ^{2} - 4 \cdot 7 ( - 24 )}{2 \cdot 7}

(- 38)^{2} - 4 \cdot 7 (- 24) = 46

p_{1, 2} = \frac{- ( - 38 ) \pm 46}{2 \cdot 7}

Separate the solutions

p_{1} = \frac{- ( - 38 ) + 46}{2 \cdot 7}, p_{2} = \frac{- ( - 38 ) - 46}{2 \cdot 7}

p = \frac{- ( - 38 ) + 46}{2 \cdot 7} : 6

p = \frac{- ( - 38 ) - 46}{2 \cdot 7} : - \frac{4}{7}

The solutions to the quadratic equation are:

p = 6, p = - \frac{4}{7}

\frac{5}{b ^{- 2}}

4 x^{2} + 29 = - 20 x

(2 + 3 i)^{2} + (2 - 3 i)^{2}

2 x - 3 (x + 5) = 2 x - (x + 3)

\frac{6 ^{\frac{1}{2}}}{6 ^{\frac{1}{3}}}

What are the solutions to the equation 7p^2-38p-24=0 ?
The solutions to the equation 7p^2-38p-24=0 are p=6,p=-4/7
Find the zeros of 7p^2-38p-24=0
The zeros of 7p^2-38p-24=0 are p=6,p=-4/7