What are the solutions to the equation -2x^2+1=0 ?

The solutions to the equation -2x^2+1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of -2x^2+1=0

The zeros of -2x^2+1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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- 2 x^{2} + 1 = 0

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

- 2 x^{2} + 1 = 0

Move

1

to the right side

- 2 x^{2} = - 1

Divide both sides by

- 2

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{3 x - 1}{9} + x = \frac{3 x + 1}{3} + 4

\frac{7 x - 1}{2 x - 3} \geq 2

lo g_{2} (M) + lo g_{2} (N) + 3

4 (3 a - b)^{2} + 20 (3 a - b) + 24

\frac{b}{6} + 5 = 13

What are the solutions to the equation -2x^2+1=0 ?
The solutions to the equation -2x^2+1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of -2x^2+1=0
The zeros of -2x^2+1=0 are x= 1/(sqrt(2)),x=-1/(sqrt(2))