What are the solutions to the equation -2x^2+11x-5=0 ?

The solutions to the equation -2x^2+11x-5=0 are x= 1/2 ,x=5

Find the zeros of -2x^2+11x-5=0

The zeros of -2x^2+11x-5=0 are x= 1/2 ,x=5

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- 2 x^{2} + 11 x - 5 = 0

x = \frac{1}{2}, x = 5

Decimal Notation

x = 0.5, x = 5

Solution steps

- 2 x^{2} + 11 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

1 1^{2} - 4 (- 2) (- 5) = 9

x_{1, 2} = \frac{- 11 \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 9}{2 ( - 2 )}, x_{2} = \frac{- 11 - 9}{2 ( - 2 )}

x = \frac{- 11 + 9}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 11 - 9}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 5

x^{2} - x - 20 > 0

\frac{12}{8}

- 12 x^{2} + 36 x = 0

4 + 4 (2 x + 1) = - 4 (x + 4) - 2 x

\frac{1}{2} x - 2 \leq 3 x - \frac{3}{2}

What are the solutions to the equation -2x^2+11x-5=0 ?
The solutions to the equation -2x^2+11x-5=0 are x= 1/2 ,x=5
Find the zeros of -2x^2+11x-5=0
The zeros of -2x^2+11x-5=0 are x= 1/2 ,x=5