What are the solutions to the equation 5z^2+20=0 ?

The solutions to the equation 5z^2+20=0 are z=2i,z=-2i

Find the zeros of 5z^2+20=0

The zeros of 5z^2+20=0 are z=2i,z=-2i

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5 z^{2} + 20 = 0

z = 2 i, z = - 2 i

Solution steps

5 z^{2} + 20 = 0

Move

20

to the right side

5 z^{2} = - 20

Divide both sides by

5

z^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 4, z = - - 4

- 4 = 2 i

- - 4 = - 2 i

z = 2 i, z = - 2 i

- 3 y \leq 15

\frac{( 2 + 3 h ) ^{2} - 4}{h}

x^{2} - 6 x = 1

6 x^{4} - 13 x^{3} - 70 x^{2} + 89 x + 60

3 ∣ 3 t + 1 ∣ = 2 ∣ 6 t + 3 ∣

What are the solutions to the equation 5z^2+20=0 ?
The solutions to the equation 5z^2+20=0 are z=2i,z=-2i
Find the zeros of 5z^2+20=0
The zeros of 5z^2+20=0 are z=2i,z=-2i