What are the solutions to the equation t^2-t-20=0 ?

The solutions to the equation t^2-t-20=0 are t=5,t=-4

Find the zeros of t^2-t-20=0

The zeros of t^2-t-20=0 are t=5,t=-4

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t^{2} - t - 20 = 0

t = 5, t = - 4

Solution steps

t^{2} - t - 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

t_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

t = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

t = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

t = 5, t = - 4

k^{2} = 4 k

5 \cdot \frac{1}{3}

\frac{1}{x} \leq 0

7 x^{2} - 7 x + 8 x y - 8 y

∣ x + 8 ∣ + 4 = 3

What are the solutions to the equation t^2-t-20=0 ?
The solutions to the equation t^2-t-20=0 are t=5,t=-4
Find the zeros of t^2-t-20=0
The zeros of t^2-t-20=0 are t=5,t=-4