What are the solutions to the equation k^2=4k ?

The solutions to the equation k^2=4k are k=4,k=0

Find the zeros of k^2=4k

The zeros of k^2=4k are k=4,k=0

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k^{2} = 4 k

k = 4, k = 0

Solution steps

k^{2} = 4 k

Move

4 k

to the left side

k^{2} - 4 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

k_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, k_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

k = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

k = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 4, k = 0

5 \cdot \frac{1}{3}

\frac{1}{x} \leq 0

7 x^{2} - 7 x + 8 x y - 8 y

∣ x + 8 ∣ + 4 = 3

(x - 2) (x + 3) = 6

What are the solutions to the equation k^2=4k ?
The solutions to the equation k^2=4k are k=4,k=0
Find the zeros of k^2=4k
The zeros of k^2=4k are k=4,k=0