What are the solutions to the equation x^2=-7-8x ?

The solutions to the equation x^2=-7-8x are x=-1,x=-7

Find the zeros of x^2=-7-8x

The zeros of x^2=-7-8x are x=-1,x=-7

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x^{2} = - 7 - 8 x

x = - 1, x = - 7

Solution steps

x^{2} = - 7 - 8 x

Move

8 x

to the left side

x^{2} + 8 x = - 7

Move

7

to the left side

x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

x_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6}{2 \cdot 1}, x_{2} = \frac{- 8 - 6}{2 \cdot 1}

x = \frac{- 8 + 6}{2 \cdot 1} : - 1

x = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 1, x = - 7

a^{4} + 2 a^{2} b^{2} + b^{4}

\frac{9 x - 1}{13} - \frac{5 x - 8}{4} = x + 6

3 x^{2} + 3 x - 1 = 0

x + 3 \leq 2 x - 7

\frac{3 x + 2}{5} + \frac{3 - 6 x}{10} = \frac{1 - x}{2}

What are the solutions to the equation x^2=-7-8x ?
The solutions to the equation x^2=-7-8x are x=-1,x=-7
Find the zeros of x^2=-7-8x
The zeros of x^2=-7-8x are x=-1,x=-7