What are the solutions to the equation x^2-12x+40=0 ?

The solutions to the equation x^2-12x+40=0 are x=6+2i,x=6-2i

Find the zeros of x^2-12x+40=0

The zeros of x^2-12x+40=0 are x=6+2i,x=6-2i

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x^{2} - 12 x + 40 = 0

x = 6 + 2 i, x = 6 - 2 i

Solution steps

x^{2} - 12 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 40 : 4 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 i}{2 \cdot 1} : 6 + 2 i

x = \frac{- ( - 12 ) - 4 i}{2 \cdot 1} : 6 - 2 i

The solutions to the quadratic equation are:

x = 6 + 2 i, x = 6 - 2 i

2 n^{2} + 19 n + 9

x^{2} + 3 x - 2 = 2

(\frac{5}{2})^{10} ((\frac{5}{4})^{5})^{- 2}

∣ 3 x - 6 ∣ + 9 = 12

6 x + 5 x = - 11

What are the solutions to the equation x^2-12x+40=0 ?
The solutions to the equation x^2-12x+40=0 are x=6+2i,x=6-2i
Find the zeros of x^2-12x+40=0
The zeros of x^2-12x+40=0 are x=6+2i,x=6-2i