What are the solutions to the equation 2x^2+x-168= 3/4 x^2+2x ?

The solutions to the equation 2x^2+x-168= 3/4 x^2+2x are x=12,x=-56/5

Find the zeros of 2x^2+x-168= 3/4 x^2+2x

The zeros of 2x^2+x-168= 3/4 x^2+2x are x=12,x=-56/5

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2 x^{2} + x - 168 = \frac{3}{4} x^{2} + 2 x

x = 12, x = - \frac{56}{5}

Decimal Notation

x = 12, x = - 11.2

Solution steps

2 x^{2} + x - 168 = \frac{3}{4} x^{2} + 2 x

Multiply both sides by

4

8 x^{2} + 4 x - 672 = 3 x^{2} + 8 x

Move

8 x

to the left side

8 x^{2} - 4 x - 672 = 3 x^{2}

Move

3 x^{2}

to the left side

5 x^{2} - 4 x - 672 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 672 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 672) = 116

x_{1, 2} = \frac{- ( - 4 ) \pm 116}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 116}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 116}{2 \cdot 5}

x = \frac{- ( - 4 ) + 116}{2 \cdot 5} : 12

x = \frac{- ( - 4 ) - 116}{2 \cdot 5} : - \frac{56}{5}

The solutions to the quadratic equation are:

x = 12, x = - \frac{56}{5}

\frac{8}{2 ( 2 + 2 )}

x^{2} - 3 x - 28 = x^{2} + 3 x - 28

2 x^{2} - 9 x = 35

3 n^{2} = 19

\frac{3}{9} \cdot \frac{3}{6}

What are the solutions to the equation 2x^2+x-168= 3/4 x^2+2x ?
The solutions to the equation 2x^2+x-168= 3/4 x^2+2x are x=12,x=-56/5
Find the zeros of 2x^2+x-168= 3/4 x^2+2x
The zeros of 2x^2+x-168= 3/4 x^2+2x are x=12,x=-56/5