What is factor d^6-64p^6 ?

The solution to factor d^6-64p^6 is (d+2p)(d^2-2dp+4p^2)(d-2p)(d^2+2dp+4p^2)

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factor d^6-64p^6

factor

d^{6} - 64 p^{6}

(d + 2 p) (d^{2} - 2 d p + 4 p^{2}) (d - 2 p) (d^{2} + 2 d p + 4 p^{2})

Solution steps

d^{6} - 64 p^{6}

d^{6} = (d^{3})^{2}

64 p^{6} = (8 p^{3})^{2}

= (d^{3})^{2} - (8 p^{3})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(d^{3})^{2} - (8 p^{3})^{2} = (d^{3} + 8 p^{3}) (d^{3} - 8 p^{3})

= (d^{3} + 8 p^{3}) (d^{3} - 8 p^{3})

Factor

d^{3} + 8 p^{3} : (d + 2 p) (d^{2} - 2 d p + 4 p^{2})

= (d + 2 p) (d^{2} - 2 d p + 4 p^{2}) (d^{3} - 8 p^{3})

Factor

d^{3} - 8 p^{3} : (d - 2 p) (d^{2} + 2 d p + 4 p^{2})

= (d + 2 p) (d^{2} - 2 d p + 4 p^{2}) (d - 2 p) (d^{2} + 2 d p + 4 p^{2})

3 b^{2} - 7 b + 2

\frac{1}{5} x + \frac{1}{6} + \frac{5}{10} = \frac{7}{10}

c^{2} - 6 c + 9

t^{2} + 3 t + 2 = 0

(- 1)^{n} (- 1)^{n}

What is factor d^6-64p^6 ?
The solution to factor d^6-64p^6 is (d+2p)(d^2-2dp+4p^2)(d-2p)(d^2+2dp+4p^2)