What is the answer to |x^2-6x|=9 ?

The answer to |x^2-6x|=9 is x=3(1-sqrt(2))\lor x=3\lor x=3(1+sqrt(2))

Solve for x: |x^2-6x|=9

The solution is x=3(1-sqrt(2))\lor x=3\lor x=3(1+sqrt(2))

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x^{2} - 6 x = 9

x = 3 (1 - 2) or x = 3 or x = 3 (1 + 2)

Decimal Notation

x = - 1.24264 \dots, x = 3, x = 7.24264 \dots

Solution steps

x^{2} - 6 x = 9

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 6 x = - 9 or x^{2} - 6 x = 9

x^{2} - 6 x = - 9 or x^{2} - 6 x = 9

x = 3 or (x = 3 (1 - 2) or x = 3 (1 + 2))

x = 3 (1 - 2) or x = 3 or x = 3 (1 + 2)

∣ 4 x - 6 ∣ \leq 14

4 x - 12 > 6

- 0.2 (x + 4) - 0.1 x = - 2.6

\frac{1}{2 ^{5}}

\frac{16 r ^{3} t ^{- 5}}{4 r ^{- 1} t ^{2}}

What is the answer to |x^2-6x|=9 ?
The answer to |x^2-6x|=9 is x=3(1-sqrt(2))\lor x=3\lor x=3(1+sqrt(2))
Solve for x: |x^2-6x|=9
The solution is x=3(1-sqrt(2))\lor x=3\lor x=3(1+sqrt(2))