What are the solutions to the equation r^2+16=0 ?

The solutions to the equation r^2+16=0 are r=4i,r=-4i

Find the zeros of r^2+16=0

The zeros of r^2+16=0 are r=4i,r=-4i

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r^{2} + 16 = 0

r = 4 i, r = - 4 i

Solution steps

r^{2} + 16 = 0

Move

16

to the right side

r^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 16, r = - - 16

- 16 = 4 i

- - 16 = - 4 i

r = 4 i, r = - 4 i

- 2 n - n + 10 \leq 12 + 10

\frac{( x + h )}{( x + h ) + 1}

2 x^{2} = 27 + 3 x

- 11 - 8 k > 23 - (7 - 4 k)

576

What are the solutions to the equation r^2+16=0 ?
The solutions to the equation r^2+16=0 are r=4i,r=-4i
Find the zeros of r^2+16=0
The zeros of r^2+16=0 are r=4i,r=-4i