What are the solutions to the equation x^2+18x-20=0 ?

The solutions to the equation x^2+18x-20=0 are x=-9+sqrt(101),x=-9-sqrt(101)

Find the zeros of x^2+18x-20=0

The zeros of x^2+18x-20=0 are x=-9+sqrt(101),x=-9-sqrt(101)

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x^{2} + 18 x - 20 = 0

x = - 9 + 101, x = - 9 - 101

Decimal Notation

x = 1.04987 \dots, x = - 19.04987 \dots

Solution steps

x^{2} + 18 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 20) = 2101

x_{1, 2} = \frac{- 18 \pm 2 101}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 101}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 101}{2 \cdot 1}

x = \frac{- 18 + 2 101}{2 \cdot 1} : - 9 + 101

x = \frac{- 18 - 2 101}{2 \cdot 1} : - 9 - 101

The solutions to the quadratic equation are:

x = - 9 + 101, x = - 9 - 101

\frac{1}{8} + \frac{1}{8} + \frac{1}{4}

- 3 x (x - 2) > 24

\frac{8}{11} \cdot 4

9 - ∣ x + 3 ∣ \geq 5

(2 x^{3})^{4}

What are the solutions to the equation x^2+18x-20=0 ?
The solutions to the equation x^2+18x-20=0 are x=-9+sqrt(101),x=-9-sqrt(101)
Find the zeros of x^2+18x-20=0
The zeros of x^2+18x-20=0 are x=-9+sqrt(101),x=-9-sqrt(101)