What are the solutions to the equation -16t^2+96t=0 ?

The solutions to the equation -16t^2+96t=0 are t=0,t=6

Find the zeros of -16t^2+96t=0

The zeros of -16t^2+96t=0 are t=0,t=6

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- 16 t^{2} + 96 t = 0

t = 0, t = 6

Solution steps

- 16 t^{2} + 96 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 0 = 96

t_{1, 2} = \frac{- 96 \pm 96}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 96}{2 ( - 16 )}, t_{2} = \frac{- 96 - 96}{2 ( - 16 )}

t = \frac{- 96 + 96}{2 ( - 16 )} : 0

t = \frac{- 96 - 96}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

t = 0, t = 6

\frac{3}{4} x - 2 = \frac{1}{8} x

245

- 5 x^{2} + 80 x - 365 = 0

∣ 2 x + 7 ∣ < 8

12 n + 20 n^{2}

What are the solutions to the equation -16t^2+96t=0 ?
The solutions to the equation -16t^2+96t=0 are t=0,t=6
Find the zeros of -16t^2+96t=0
The zeros of -16t^2+96t=0 are t=0,t=6