What are the solutions to the equation v^2=0+2*2.11*5.84 ?

The solutions to the equation v^2=0+2*2.11*5.84 are v=(sqrt(15403))/(25),v=-(sqrt(15403))/(25)

Find the zeros of v^2=0+2*2.11*5.84

The zeros of v^2=0+2*2.11*5.84 are v=(sqrt(15403))/(25),v=-(sqrt(15403))/(25)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} = 0 + 2 \cdot 2.11 \cdot 5.84

v = \frac{15403}{25}, v = - \frac{15403}{25}

Decimal Notation

v = 4.96435 \dots, v = - 4.96435 \dots

Solution steps

v^{2} = 0 + 2 \cdot 2.11 \cdot 5.84

Simplify

0 + 2 \cdot 2.11 \cdot 5.84 : 24.6448

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 24.6448, v = - 24.6448

24.6448 = \frac{15403}{25}

- 24.6448 = - \frac{15403}{25}

v = \frac{15403}{25}, v = - \frac{15403}{25}

\frac{19}{3} - \frac{2}{8}

2 x^{3} + 7 x^{2} y - 4 x y^{2}

11 p^{2} - 17 p - 20 = p^{2}

\frac{( \frac{a}{b} + 1 )}{( \frac{b}{a} - 1 )}

X^{2} - 9 = 0

What are the solutions to the equation v^2=0+2*2.11*5.84 ?
The solutions to the equation v^2=0+2*2.11*5.84 are v=(sqrt(15403))/(25),v=-(sqrt(15403))/(25)
Find the zeros of v^2=0+2*2.11*5.84
The zeros of v^2=0+2*2.11*5.84 are v=(sqrt(15403))/(25),v=-(sqrt(15403))/(25)