What are the solutions to the equation 11p^2-17p-20=p^2 ?

The solutions to the equation 11p^2-17p-20=p^2 are p= 5/2 ,p=-4/5

Find the zeros of 11p^2-17p-20=p^2

The zeros of 11p^2-17p-20=p^2 are p= 5/2 ,p=-4/5

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11 p^{2} - 17 p - 20 = p^{2}

p = \frac{5}{2}, p = - \frac{4}{5}

Decimal Notation

p = 2.5, p = - 0.8

Solution steps

11 p^{2} - 17 p - 20 = p^{2}

Move

p^{2}

to the left side

10 p^{2} - 17 p - 20 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 10 ( - 20 )}{2 \cdot 10}

(- 17)^{2} - 4 \cdot 10 (- 20) = 33

p_{1, 2} = \frac{- ( - 17 ) \pm 33}{2 \cdot 10}

Separate the solutions

p_{1} = \frac{- ( - 17 ) + 33}{2 \cdot 10}, p_{2} = \frac{- ( - 17 ) - 33}{2 \cdot 10}

p = \frac{- ( - 17 ) + 33}{2 \cdot 10} : \frac{5}{2}

p = \frac{- ( - 17 ) - 33}{2 \cdot 10} : - \frac{4}{5}

The solutions to the quadratic equation are:

p = \frac{5}{2}, p = - \frac{4}{5}

\frac{( \frac{a}{b} + 1 )}{( \frac{b}{a} - 1 )}

X^{2} - 9 = 0

e^{\frac{iπ}{2}}

ab + b c + b^{2} + a c

4 b^{2} + 8 b + 7 = 4

What are the solutions to the equation 11p^2-17p-20=p^2 ?
The solutions to the equation 11p^2-17p-20=p^2 are p= 5/2 ,p=-4/5
Find the zeros of 11p^2-17p-20=p^2
The zeros of 11p^2-17p-20=p^2 are p= 5/2 ,p=-4/5