What are the solutions to the equation 4b^2+8b+7=4 ?

The solutions to the equation 4b^2+8b+7=4 are b=-1/2 ,b=-3/2

Find the zeros of 4b^2+8b+7=4

The zeros of 4b^2+8b+7=4 are b=-1/2 ,b=-3/2

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4 b^{2} + 8 b + 7 = 4

b = - \frac{1}{2}, b = - \frac{3}{2}

Decimal Notation

b = - 0.5, b = - 1.5

Solution steps

4 b^{2} + 8 b + 7 = 4

Move

4

to the left side

4 b^{2} + 8 b + 3 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

b_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- 8 + 4}{2 \cdot 4}, b_{2} = \frac{- 8 - 4}{2 \cdot 4}

b = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

b = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

b = - \frac{1}{2}, b = - \frac{3}{2}

5 x^{2} + 12 x < 9

8 t^{4} - 32 t^{3} + t - 4

3 m^{2} + 11 mn + 6 n^{2}

\frac{5}{2} \cdot \frac{1}{4}

9 x^{2} - 42 x + 49

What are the solutions to the equation 4b^2+8b+7=4 ?
The solutions to the equation 4b^2+8b+7=4 are b=-1/2 ,b=-3/2
Find the zeros of 4b^2+8b+7=4
The zeros of 4b^2+8b+7=4 are b=-1/2 ,b=-3/2