What is the answer to 6[4-2(7y-1)]=8(13-8y) ?

The answer to 6[4-2(7y-1)]=8(13-8y) is y=-17/5

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6[4-2(7y-1)]=8(13-8y)

6 [4 - 2 (7 y - 1)] = 8 (13 - 8 y)

y = - \frac{17}{5}

Decimal Notation

y = - 3.4

Solution steps

6 [4 - 2 (7 y - 1)] = 8 (13 - 8 y)

Expand

6 (4 - 2 (7 y - 1)) : - 84 y + 36

Expand

8 (13 - 8 y) : 104 - 64 y

- 84 y + 36 = 104 - 64 y

Move

36

to the right side

- 84 y = - 64 y + 68

Move

64 y

to the left side

- 20 y = 68

Divide both sides by

- 20

y = - \frac{17}{5}

3 - \frac{2 x}{3} < \frac{1}{2} + \frac{3 x}{4}

5 + 3

(\frac{2}{5} m^{2} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 m n^{- 3})

4 x + 2 - 15 < - 1

x^{2} + 7 x - 45 = 7

What is the answer to 6[4-2(7y-1)]=8(13-8y) ?
The answer to 6[4-2(7y-1)]=8(13-8y) is y=-17/5
Solve for y: 6[4-2(7y-1)]=8(13-8y)
The solution is y=-17/5