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Popular >

|x+2|+1>= 7

Solution

∣ x + 2 ∣ + 1 \geq 7

Solution

x \leq - 8 or x \geq 4

+1

Interval Notation

(- \infty, - 8] \cup [4, \infty)

Solution steps

∣ x + 2 ∣ + 1 \geq 7

Move

1

to the right side

∣ x + 2 ∣ \geq 6

Apply absolute rule: If

∣ u ∣ \geq a, a > 0

then

u \leq - a

or

u \geq a

x + 2 \leq - 6 or x + 2 \geq 6

x + 2 \leq - 6 or x + 2 \geq 6

x \leq - 8 or x \geq 4

Popular Examples

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49 a^{2} - 28 a + 4

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x^{2} - 3 x - 2 = 0

5 x^{2} + 3 x + 1 = 0

simplify ((-1)/2)/((sqrt(3))/2)simplify

\frac{\frac{- 1}{2}}{\frac{3}{2}}

10 x + 9 \leq 5 + 9

Frequently Asked Questions (FAQ)

What is |x+2|+1>= 7 ?
The solution to |x+2|+1>= 7 is x<=-8\lor x>= 4