What are the solutions to the equation (3x+2)^2=10 ?

The solutions to the equation (3x+2)^2=10 are x=(sqrt(10)-2)/3 ,x=(-sqrt(10)-2)/3

Find the zeros of (3x+2)^2=10

The zeros of (3x+2)^2=10 are x=(sqrt(10)-2)/3 ,x=(-sqrt(10)-2)/3

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(3 x + 2)^{2} = 10

x = \frac{10 - 2}{3}, x = \frac{- 10 - 2}{3}

Decimal Notation

x = 0.38742 \dots, x = - 1.72075 \dots

Solution steps

(3 x + 2)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 10 : x = \frac{10 - 2}{3}

Solve

3 x + 2 = - 10 : x = \frac{- 10 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{10 - 2}{3}, x = \frac{- 10 - 2}{3}

∣ 2 x - 1 ∣ + 3 = 3

2 x + \frac{x + 5}{6} - \frac{3 ( x + 4 )}{8} = 7 - 3 x

∣ x - 1 ∣ \leq x

∣ z ∣ = - 4

What are the solutions to the equation (3x+2)^2=10 ?
The solutions to the equation (3x+2)^2=10 are x=(sqrt(10)-2)/3 ,x=(-sqrt(10)-2)/3
Find the zeros of (3x+2)^2=10
The zeros of (3x+2)^2=10 are x=(sqrt(10)-2)/3 ,x=(-sqrt(10)-2)/3