What are the solutions to the equation -3.9x^2+6.7x=1.4 ?

The solutions to the equation -3.9x^2+6.7x=1.4 are x=(67-sqrt(2305))/(78),x=(67+sqrt(2305))/(78)

Find the zeros of -3.9x^2+6.7x=1.4

The zeros of -3.9x^2+6.7x=1.4 are x=(67-sqrt(2305))/(78),x=(67+sqrt(2305))/(78)

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- 3.9 x^{2} + 6.7 x = 1.4

x = \frac{67 - 2305}{78}, x = \frac{67 + 2305}{78}

Decimal Notation

x = 0.24345 \dots, x = 1.47449 \dots

Solution steps

- 3.9 x^{2} + 6.7 x = 1.4

Multiply both sides by

10

- 39 x^{2} + 67 x = 14

Move

14

to the left side

- 39 x^{2} + 67 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 67 \pm 6 7 ^{2} - 4 ( - 39 ) ( - 14 )}{2 ( - 39 )}

6 7^{2} - 4 (- 39) (- 14) = 2305

x_{1, 2} = \frac{- 67 \pm 2305}{2 ( - 39 )}

Separate the solutions

x_{1} = \frac{- 67 + 2305}{2 ( - 39 )}, x_{2} = \frac{- 67 - 2305}{2 ( - 39 )}

x = \frac{- 67 + 2305}{2 ( - 39 )} : \frac{67 - 2305}{78}

x = \frac{- 67 - 2305}{2 ( - 39 )} : \frac{67 + 2305}{78}

The solutions to the quadratic equation are:

x = \frac{67 - 2305}{78}, x = \frac{67 + 2305}{78}

3 5 x^{2} - 16 x - 75

0.4 \cdot 3

- 0 - 7 n - 0.014 + 0.15 n > 0.026

(\frac{3 x ^{\frac{3}{2}} y ^{3}}{x ^{2} y ^{- \frac{1}{2}}})^{- 2}

What are the solutions to the equation -3.9x^2+6.7x=1.4 ?
The solutions to the equation -3.9x^2+6.7x=1.4 are x=(67-sqrt(2305))/(78),x=(67+sqrt(2305))/(78)
Find the zeros of -3.9x^2+6.7x=1.4
The zeros of -3.9x^2+6.7x=1.4 are x=(67-sqrt(2305))/(78),x=(67+sqrt(2305))/(78)