What are the solutions to the equation 2x^2+6=0 ?

The solutions to the equation 2x^2+6=0 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 2x^2+6=0

The zeros of 2x^2+6=0 are x=sqrt(3)i,x=-sqrt(3)i

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2 x^{2} + 6 = 0

x = 3 i, x = - 3 i

Solution steps

2 x^{2} + 6 = 0

Move

6

to the right side

2 x^{2} = - 6

Divide both sides by

2

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

r^{2} - 11 r + 30 = 0

\frac{x - 3 y}{x + y} + \frac{x + 5 y}{x + y}

m^{2} - 4 m - 5

x^{2} + 8 x - 84 = 0

\frac{1}{27} y^{9} - \frac{27}{1000} x^{12}

What are the solutions to the equation 2x^2+6=0 ?
The solutions to the equation 2x^2+6=0 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 2x^2+6=0
The zeros of 2x^2+6=0 are x=sqrt(3)i,x=-sqrt(3)i